15x^2+8x=16

Solution for 15x^2+8x=16 equation:

15x^2+8x=16

We move all terms to the left:

15x^2+8x-(16)=0

a = 15; b = 8; c = -16;
Δ = b2-4ac
Δ = 82-4·15·(-16)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-32}{2*15}=\frac{-40}{30}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+32}{2*15}=\frac{24}{30}
=4/5
$